bash - PHP: How to get the error message of failed shell command? -

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i execute following command make database backup:

$exec = exec("mysqldump --opt                          --user=$database_user                          --password=$database_pass                          --host=$database_host                          $database_name > $output_filename", $out, $status);

to check if mysqldump failed do:

if ($status == 0) {    // ok } else {    // error    // how print error message here ? }

in case goes wrong , mysqldump fails, how error message ?

you can use proc_open (as suggested emil). below more complete example of how achieve want.

$exec_command = "mysqldump --opt                      --user=$database_user                      --password=$database_pass                      --host=$database_host                      $database_name"  $descriptorspec = array(                        0 => array("pipe", "r"),  // stdin pipe                         1 => array("file", $output_filename, "w"),  // stdout file                          2 => array("pipe", "w")   // stderr pipe  );  $proc = proc_open($exec_command, $descriptorspec, $pipes);  fwrite($pipes[0], $input); //writing std_in fclose($pipes[0]);  $err_string = stream_get_contents($pipes[2]); //reading std_err fclose($pipes[2]);   $return_val = proc_close($proc);

edit:

changed output write file


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