c++ - Is p = array the same as p = &array[0]? -

- 

int numbers[20]; int * p;

are 2 assignments below same?

p = numbers; p = &numbers[0];

yes both same.

in case, name of array decays pointer first element.

hence, 

p = numbers;       //name of array

is same as:

p = &numbers[0];   //address of first element of array

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