ajax - How do i pass a variable in the xmlhttp.send function -

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how pass variable in xmlhttp.send function 

var str = "hello" xmlhttp.open("post","./omnama.php",true); xmlhttp.setrequestheader("content-type","application/x-www-form-urlencoded"); xmlhttp.send("fname=+str"); ' fills database str not hello

i tried these not working 

 xmlhttp.send("fname=" +str,"lname=" +cool);

it fills fname variable value not lname, lname gives empty string how combine if have many variables pass on ?

xmlhttp.send("fname=" + str); should work  xmlhttp.send("fname=" +str + "&lname=" +cool);

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