lxml - Error With AlchemyAPI Python SDK -

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i trying use alchemyapi python 0.7 sdk. when ever run method within e.g. urlgettext(url);

i error:

    nodes = etree.fromstring(result).xpath(xpathquery)   file "lxml.etree.pyx", line 2743, in lxml.etree.fromstring (src/lxml/lxml.etree.c:52665)   file "parser.pxi", line 1573, in lxml.etree._parsememorydocument (src/lxml/lxml.etree.c:79932)   file "parser.pxi", line 1452, in lxml.etree._parsedoc (src/lxml/lxml.etree.c:78774)   file "parser.pxi", line 960, in lxml.etree._baseparser._parsedoc (src/lxml/lxml.etree.c:75389)   file "parser.pxi", line 564, in lxml.etree._parsercontext._handleparseresultdoc (src/lxml/lxml.etree.c:71739)   file "parser.pxi", line 645, in lxml.etree._handleparseresult (src/lxml/lxml.etree.c:72614)   file "parser.pxi", line 585, in lxml.etree._raiseparseerror (src/lxml/lxml.etree.c:71955) lxml.etree.xmlsyntaxerror: attvalue: " or ' expected, line 19, column 11

this come area of code:

  def getrequest(self, apicall, apiprefix, paramobject):     endpoint = 'http://' + self._hostprefix + '.alchemyapi.com/calls/' + apiprefix + '/' + apicall     endpoint += '?apikey=' + self._apikey + paramobject.getparameterstring()     handle = urllib.urlopen(endpoint)     result = handle.read()     handle.close()     xpathquery = '/results/status'     nodes = etree.fromstring(result).xpath(xpathquery)     if nodes[0].text != "ok":       raise exception, 'error making api call.'     return result

any 1 have ideas going wrong?

thank you

daniel kershaw

i looked @ python urllib docs, , found page:

http://docs.python.org/library/urllib.html#high-level-interface

which contains warning filehandle object returned urllib.urlopen():

one caveat: read() method, if size argument omitted or negative, may not read until end of data stream; there no way determine entire stream socket has been read in general case.

i think maybe should ensure obtain entire contents of file python string before parsing etree.fromstring() api. like:

result = '' while (1):     next = handle.read()     if not next:          break     result += next

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