c - fscanf bus error: 10 when switching from Snow Leopard to Lion -

first off, snippet not meant production code. please, no lecturing "being unsafe." thanks!

so, following code part of parser takes in csv , uses populate sqlite3 db. when compiled , ran in snow leopard, worked fine. i've switched lion, scanf statement throws bus error: 10. specifically, seems have how consuming , discarding '\n' @ end of each line:

int main() {   sqlite3* db;   sqlite3_open("someexistingdb.sqlite3", &db);    file *pfile;   pfile = fopen("exceldata.csv","r");    char name[256],country[256], last[256], first[256], photouri[256];   char sqlstatement[16384];    while(fscanf(pfile, "%[^,],%[^,],%[^,],%[^,],%[^\n]%*c", name, country, last,first, photouri) != eof)   {           blah...     ... 

if remove last %*c, meant consume '\n' , ignore advance next line, program not crash. of course incorrect parsing.

also, mind you, eof doesn't seem problem; i'e tried single fscanf statement instead of while-loop shown above.

any thoughts?

edit: let me add code compiled , ran in intel core duo (32-bit) macbook snow leopard , compiling , running on macpro (64-bit) lion. wonder if might have alignment?

interesting. bus errors due alignment issues may not case here since you're scanning in chars.

one thing may want consider fgets entire line buffer , sscanf it. allow 2 things:

• print out line in debug statement before sscanfing (or after scanning, if expected conversion count wrong), can see if there problems; and
• not worry trying align line-ending fscanf, since fgets job of already.

so (untested):

char bighonkinbuffer[16384]; while (fgets (bighonkinbuffer, sizeof(bighonkinbuffer), pfile) != null) {     if (sscanf(bighonkinbuffer, "%[^,],%[^,],%[^,],%[^,],%[^\n]", name, country, last,first, photouri) != 5) {         // printf ("not scanned properly: [%s]\n", bighonkinbuffer);         exit (1);     } } 

you should check return values sqlite3_open , fopen calls, if more "play" code (i.e., if there's slightest possibility files may not exist).