mysql - How to select a product from SQL where code and id -


i have sql table:

create table if not exists `orders` (   `id` int(11) not null auto_increment,   `order_name` text not null,   `order_q` text not null,   `order_price` text not null,   `order_id` text not null,   `code` text not null,   `order_date` text not null,   `stat` text not null,   primary key  (`id`) ) engine=myisam  default charset=cp1256 auto_increment=6 ; 

i want print out rows 1 one order 2 rows:

1- order_id  2- code 

this script looks shopping script, when clients making order, script automatically printing out invoice.

what should do?

my code:

<?     include("config.php");     $print = 'onload="window.print();     "'; $code_num="123456";     $result = mysql_query("select * orders stat='0' && code='$code_num' order id asc limit 1");     while($row = mysql_fetch_array($result))     {         echo $row[order_name];     } ?> 

i not sure you're trying do, following code trick? haven't tested it, it's pretty straightforward. see sql order keyword , php mysql order keyword.

$query = "select * orders order order_id, code"; $result = mysql_query($query)or die(mysql_error());  while($row = mysql_fetch_array($result)){     echo $row['order_name'];//echo parts need } 

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