bash - extract file name from full file name -

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#!/bin/bash files=src/*.erl shopt -s nullglob f in $files   echo "processing $f file..." # ??? done

how can extract file name full path? , mean - "pathfilename=${f%.*}"?

i'll copy help-output, since has examples , everything.

~$ basename --help usage: basename name [suffix]   or:  basename option print name leading directory components removed. if specified, remove trailing suffix.        --help     display , exit       --version  output version information , exit  examples:   basename /usr/bin/sort       output "sort".   basename include/stdio.h .h  output "stdio".

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