list - Consolidating this J code -

i'm learning j , starting basic; adding multiples of 3 , 5 below 100. got code:

(+/((((i.100)|~ 3) = 0) # (i.100)),((((i.100)|~ 5) = 0) # (i.100)))-(((i.100|~15)=0) # (i.100)) 

but seems there should easier way. there way make code cleaner? thanks.

note current code gives length error have suggested edit question make work. i'll include working code below.

(+/((((i.100)|~ 3) = 0) # (i.100)),((((i.100)|~ 5) = 0) # (i.100))) - (+/(((i.100)|~15)=0) # (i.100)) 

the same algorithm can written more (less parentheses anyway) altering order of operations (j evaluates "sentences" right left).

   (+/ ((0 = 3|i.100) # i.100) , ((0 = 5|i.100) # i.100)) - +/(0 = 15|i.100)#i.100 2318 

rather subtracting sum of multiples of 15 original sum avoid double counting number multiples of both 3 , 5, use ~. (nub) remove duplicates list of multiples of 3 , multiples of 5 before summing them.

   +/ ~. ((0 = 3|i.100) # i.100) , (0 = 5|i.100) # i.100 2318 

for more jish approach problem see answer this stackoverflow question.